Scribepost for January.7

QUESTION 6:Determine the length of the leg for each right triangle

The side length of the leg is 24 cm.

B)




The side length of the leg is 10 cm.

scribepost for january 6 , 09

7. what is the height of the wheel chair ramp?give your answer to the nearest tenth of a centimetre .

c squared - b squared = a squared

80 squared - 79 squared = a squared

(80x80)- (79x79)= a squared

6400- 6241 = a squared

159 = a squared

square roots of 159 = square roots of a squared

a squared = 12.6cm

the wheelchair ramp would be 12.6cm tall

Scribepost for January 7 , 2010 .

Sorry if some other person did this question already , but anyways here you go :)

page 110 .

# 3. Walter walks across a rectangular field in a diagonal line . Maria walks around two sides of the field . They meet at the opposite corner .

a) How far did Maria walk ?
120m + 300m = 420m . Maria walked 420m .

b) How far did Walter walk ? Express your answer to the nearest meter .

a2 + b2 = c2
3002m + 1202m = c2
( 300 x 300 ) + ( 120 x 120 ) = c2
90 000 + 240 = c2
c2 = 90 240 SQUARED .
c2 = 300.3m .

c ) Who walked farther ? By how much ?
Maria walked farther by 119.7 m .



there you go , please comment !

Connor's Scribepost for January 6, 2010

Hello I'm Connor, I am going to be showing the class how I did question 7.

Numero 7 =)

What is the height of the wheelchair ramp? Answer the question to the nearest tenth of a centimeter.

How I got my answer...

So the height of the ramp is 12.6 cm tall.

Thanks to whoever read this and please comment.

Argie's Scribepost for Jan 6 2010

Hi my name is Argie, I had to do a scribepost and I chose question 4 on page 110.

4) Find the height of the pole where the guy wire is attached, round to the nearest tenth of a meter.

c² - a² = b²

10² - 2² = b²

10x10 - 2x2 = b²

100 - 4 = b²

96 = b²

√96 = √b²

9.7m = b

The height of the pole would be 9.7m.

PLEASE COMMENT, THANKS FOR READING.

Mary Jane's Scribepost for January 6, 2010

I chose to do my scribe post on question number 14 on page 113.

Find the missing side length of each triangle.




a) a² + b² = c²
12² + 5² = c²
(12x12) + (5x5) = c²
144 + 25 = c²
169 = c²
√169 = √c²
13 = c





The length of c also known d is 13m.






b) c² - a² = b²
15² - 9² = b²
(15x15) - (9x9) = b²
225 - 81 = b²
144 = b²
√144 = √b²
12 = b

The length of b also known as v is 12cm.

REMINDER: study for the quiz tomorrow!
Tip: Do the practice questions in the math links. You could go to mytextbook.ca to find these questions.

Gilbert Scribepost for January 6 2009

OK today in class Mr. Harbeck told the people who didn't do a scribe yet to pick a question and do one scribe.
OK so I chose number 7

7.What is the height of the wheelchair ramp? Give your answer to the nearest tenth of a centimeter.
Formula

c² - b² = a²

80² - 79² = a²

(80x80) - (79-79) = a²

6400 - 6241 = a²

159 = a²

√159 = √a²

12.6cm= a

Simple sentence answer- The height of the wheel chair ramp would be 12.6 cm high

PLEASE COMMENT THANK YOU !

Scribepost for January 6th 2010

The question I chose to do is number 4 from page 110.

You want to find out the height of the pole where the guy wire is attached, to the nearest tenth of a meter.

The triangle isn't labeled as A,B,or C, my mistake.





c²-b²=a²
10²-2²=a²
(10x10)-(2x2)=a²
100-4=a²
96=a²
√96=√a²
9.8=a

Scribepost for January 6, 2010

Today in class Mr.Harbeck told us to choose any question from 110-113 so I am doing question 6~!

You are asked to check the design plans for a baseball diamond. Is the triangle a right triangle? Explain.

I don't think its a right triangle because on either side of the baseball diamond its still not a right triangle. 

P.S I know that you don't get this but the thing is that without a picture you still wont know so thats why I don't know how to rotate a picture in paint!     D:!

Celdrick's Scribepost for January 6 2009

Hello.... Today in class all of the people who didn't scribble had to do one question and do a scribe about it.
(sorry my computer won't let me add colors for the letters)


I chose question 7.

7. What is the height of
the wheelchair ramp?
Give your answer to
the nearest tenth of a centimetre.












First I did the formula.













Simple sentence answer: The height of the wheel chair ramp would be 12.6 cm high





Don't forget to



C
Co
Com
Comm
Comme
Commen
Comment

Scribepost For January 6 2009

Today Mr. Harbeck said that if we haven't scribe yet we should pick a question. Here is question number 7.

7. What is the height of
the wheelchair ramp?
Give your answer to
the nearest tenth of a centimetre.

c² - b² = a²

80² - 79² = a²

(80x80) - (79-79) = a²

6400 - 6241 = a²

159 = a²

√159 = √a²

12.6cm= a

The wheelchair ramp would be 12.6 cm tall.

Thanks for reading my scribe!

Please Leave A Comment! (:

Elaine's Scribepost for January 6, 2009

For my scribepost, I chose to do question 7.

#7)
What is the height of the wheelchair ramp? Give your answer to the nearest tenth of a centimetre.





After I got my answer, I round it to the nearest tenth of a centimeter.

The height is 12.6 cm.















Thanks for reading my scribe!! Please leave a comment.

Scribepost for January 6, 2010

Shahriar knows that the size of a computer monitor is based on the lenght of the diagonal on the screen. He thinks that the diagonal is not as large as the ad says. Is he correct? Explain.

a squared+b squared = c squared

25 square+3o squared = c squared

(25x25)+(30x30) = c squared

625+900=

1525= c squared

He is correct because the right lenght is 39 cm.

Please comment!

Scribepost for January 6, 2010

Hi everybody. 'Im Jex and today we had to work on pages 109-113 to help us do good on the quiz . So I'm doing question 14.


Find the missing side length of each triangle.








Don't Forget to Study for the quiz tomorrow.

scribepost 01.06.10

Here's my scribe post for today. I'm doing question 8.

Shahriar knows that the size of a computer monitor is based on the length of the diagonal of the screen. He thinks that the diagonal is not as large as the ad says. is he correct? Explain.

The ad says " GREAT DEAL 42-cm monitor on sale!"

ANSWER:
a²+b²=c²
25²+30²=c²
(25x25)+(30x30)=c²
625+900=c²
√1525=√c
39.05cm

Shahriar is correct. the ad was wrong. The exact length is 39.05 cm

sorry, no pictures.

PLEASE COMMENT :)

Scribepost for January 6

Today Mr.Harbeck said to do questions.

So i am going to do question #14 in page 113.

Noelle's Scribepost for Jan 5

YO, whats up guys. I'm supposed to do question number 15. Here was the question.
(no pictures, sorry)

the coordinate grid shown was drawn on centimetre grid paper. What is the length of line segment AB? Express your answer to the nearest tenth of a centimeter.

We have to find the length of a diagonal line on centimeter grid paper. In order to get from one point to the other point, you have to go up 4 squares and over 2 squares. So the length of the line is approximately 6 squares, because 4+2=6.

I know it's complicated without pictures, but there's my work.
COWMENT !

Larrisa's scribepost January 5 , 2010

A²+B²=C²
7²+5²=C²
(7x7)+(5x5)=C²
49+25=C²
Square root of 74=C²
8.6=C²
8.6=Diameter

The diameter of the circle is 8.6 cm.


COMMENT !

Scribepost for January 5, 2010

Question #16

What is the length of the red diagonal in the box? Express your answer to the nearest tenth of a millimetre.

a2 + b2 = c2
7 squared + 12 squared = c2
( 7 x 7 ) + (12 x 12 ) = c2
49 + 144 = c2
193 = c2
square root of 193 = square root of c2
13.9 mm = c2

a2 + b2 = c2
5 squared + 13.9 squared = c2
( 5 x 5 ) + ( 13.9 x 13.9 ) = c2
25 + 193.2 = c2
218.2 = c2
square root of 218.2 = square root of c2
14.8 mm = c2

The length of the red diagonal line is 14.8 mm.

THANKS TO JERIC AN JOMARI FOR HELPING MEE =D

Scribepost January.5 2009

Question #9
Tina wants to construct a path along the diagonal of her yard. What Length will the path be? Express your answer to the nearest tenth of a metre.






a 2 + b 2 = c 2
6 2 + 12 2 = c 2
(6x6)+(12x12) = c 2
36 + 144 = c2
The square root of 180 = the square root of c 2
13.4 = c

The length of the path is 13.4 m



sooo yeah comment =)