Tuesday, January 5, 2010

April's scribepost for Jan.5'10.










First, we have to find the length of b.











Next, we have to find the length of c.












Simple sentence answer: The length of b is 4m, and the length of c is 7.2m.

THANKYOU FOR READING MY SCRIBEPOST. PLEASE LEAVE A COMMENT. :)

Scribepost for Jan. 5

Question. 10

What is the minimum distance the player at third base has to throw the ball to get the runner out at first base? Express your answer to the nearest tenth of a metre.

A squared + B squared = C squared
27 squared + 27 squared = C squared
27x27 + 27x27 = C squared
729 + 729 = C squared
1458 = C squared
Square root of 1458 = Square root of C squared
38.18 = C squared

The distance is 38m

Brendan's Scribepost for January 5, 2010.

13. Determine the length of the base of the large triangle. Express your answer to the nearest tenth of a millimetre.













c²-a²=b²

10²-8²=b²

(10x10)-(8x8)=b²

100-64=b²

36=b²

√36=√b²

6=b


The length of the base of the large triangle is 12 mm.


Jamie's Scribepost for January 4, 2010

Question 7
A) i² - g² = h²
9² - 5² =
81 - 25 =
56 = h²
square root of 56 = h
7.48 = h
B) r² - q² = p²
15² - 11² = p²
225 - 121 = p²
104 = p²
square root of 104 = p
10.20 = p

Thank you for reading my scribe and please leave a comment!

PS: Sorry if my scribe was late, it was because I thought I had posted mine last night, but it actually didn't.

Monday, January 4, 2010

Scribepost for January 4, 2010

QUESTION 6:
Determine the length of the leg for each right triangle.









The side length of the leg is 24 cm.

















The side length of the leg is 10 cm.







DON'T FORGET TO COMMENT :)

Brayden's Scribepost January 4th, 2010

Textbook Questions

3) Determine the length of each hypotenuse.




A) 20 cm

12 cm = 144 cm²
16 cm = 256 cm²
144 cm² + 256 cm² = 400 cm²
Square of 400 cm² = 20 cm

B) 34 cm

16 m = 256 m²
30 m = 900 m²
256 m² + 900 m² = 1156 m²
Square of 1156 m² = 34 m


4) What is the length of each hypotenuse? Give your answer to the nearest tenth of a centimeter.



A) 9.2 cm

7 cm = 49 cm
²
6 cm = 36 cm²
49 cm² + 36 cm² = 85 cm²
Square of 85 cm² = 9.2 cm

B) 13.6 cm

11 cm = 121 cm²
8 cm = 64 cm²
121 cm² + 64 cm² = 185 cm²
Square of 185 cm² = 13.6 cm

COMMENT!

Sharmaine's Scibe post for Jan.4, 2010

Textbook Question

Question #5:



A.) What is the area of the square attached to the legs of the right triangle?

6cm x 6cm = 36cm squared
8cm x 8cm = 64cm squared

B.) What is the area of the square attached to the hypotenuse?

formula: a squared + b squared = c squared
36cm squared + 64cm squared = 100cm squared
The area of the hypotenuse is 100cm squared.

C.) What is the length of the hypotenuse?

The square root of 100cm squared is 10cm.

THANKS FOR READING!
DON'T FORGET TO COMMENT!

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