Here is my work showing how to get the hypotenuse
The portion for this problem is..
a² + b² = c²
6² + 10² = c²
(6x6)+(10x10)=c²
36 + 100 = c²
136 = c²
√136 = √c²
√136 = 11.66
The length of the hypotenuse also labeled as h is 11.66cm
Thursday, April 29, 2010
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